Thanks for contributing an answer to Mathematics Stack Exchange! Please be sure to answer the question. Provide details and share your research! But avoid … Asking for help, clarification, or responding to other answers. Making statements based on opinion; back them up with references or personal experience. Use MathJax to format equations. physics gravity problem ? If nothing cab go 186,000 miles per second according to Einstein, how can light go that fast? A 6 m ladder weighs 350N and is placed with its lower end on a horizontal floor and its upper end against the wall. Professional supplies and tutorials for the Fx and Cosplay world. The magnitude of the force is given by F = ma = (10) (5) = 50 N. It acts over a distance of 20 m, in the same direction as the displacement of the object, implying that the total work done by the force is given by W = Fx = (50) (20) = 1000 Joules. Problem : A ball is connected to a rope and swung around in uniform circular motion. The tension in the rope is measured at 10 N and the radius of the circle is 1 m. f (x) ( / ˌɛf ˈɛks /; Korean : 에프엑스) is a South Korean multinational girl group formed by SM Entertainment. The group's composed of Victoria, Amber, Luna, and Krystal and previously Sulli until her departure from the group in August 2015. f (x) officially debuted in September 2009 with the release of the digital single "La Cha Ta".

## Yes it is possible but it depends that on which direction f component is acting . Cos theta = base / hypotenuse . Hope it is clear . There are several examples

W = F d. W = work (Joules). F = force (Newtons) d = displacement (metres) calculate the the side adjacent to the angle. cos = adj hyp. =Fx/F. Fx=F cos . Constant colinear force: W = F x x = distance traveled. 2. Constant non-colinear force: W = F • Δr = F Δr cos θ = Fx Δx + A joule, in terms of fundamental units, is easily calculated: W = Fx = (m) = The joule is a multipurpose unit. It serves not only as a unit of work, but also of energy. 30 Mar 2017 Principle 1- work over a closed loop W = Fx.cos(q) W(up) = mgh.cos(180) = -mgh W(down) =mgh.cos(0) = mgh Total Work = -mgh + mgh = 0; 11 Yes it is possible but it depends that on which direction f component is acting . Cos theta = base / hypotenuse . Hope it is clear . There are several examples

### Why does one need a cos and theta when we can easily get the work by matter because the y component is going vertical and doesn't do anything to with the

30 Mar 2017 Principle 1- work over a closed loop W = Fx.cos(q) W(up) = mgh.cos(180) = -mgh W(down) =mgh.cos(0) = mgh Total Work = -mgh + mgh = 0; 11 Yes it is possible but it depends that on which direction f component is acting . Cos theta = base / hypotenuse . Hope it is clear . There are several examples We shall start with the sine function, f(x) = sin x. This function can be number x using a diagram like this. x cos x. 1 www.mathcentre.ac.uk. 5 c mathcentre 2009

### functions and W is a space of trigonometric polynomials. sin(kt) and cos(kt), 1 ≤ k ≤ m constitute an orthogonal basis for Tm. Let f(x) be the sign–function.

tions f(x) with period L = 2π. Their fundamental frequency is then k = 2π. L. = 1, and their Fourier series representations involve terms like a1 cos x , b1 sin x.

## f(x) cos nπx. L dx, n = 1,2, Detailed solution: We search for the solution of the boundary value problem as a superposition of solutions u(x, y) = φ(x)h(y) with

Suppose z=f(x,y) is a function of two variables with a domain of D. Let (a,b)∈D and define u=cosθi+sinθj. Then the directional derivative of f in the direction of u cos(t. = f='o -1 (2n)!s4n+l·. 12. Given that Q(s) is a polynomial with n distinct zeros, we may conditions are that for both u(x,y) and f(x,y) all first partial derivatives. Integrate f(x, y) = (x + y + 1)−2 over the triangle with vertices (0, 0),. (4, 0), and (0, Compute the double integral of f(x, y) = cos(2x + y) over the domain. 1/2 ≤ x (a) There exists a function f with continuous second partial derivatives such that fx (x fx(x, y) = 2 cos(2x + 3y) Find the differential of the function: v = y cos(xy).